f(-2)=3(-2)^2+2(-2)-5

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Solution for f(-2)=3(-2)^2+2(-2)-5 equation: 



f(-2)=3(-2)^2+2(-2)-5

We move all terms to the left:

f(-2)-(3(-2)^2+2(-2)-5)=0

We add all the numbers together, and all the variables

f(-2)-3=0

We multiply parentheses

-2f-3=0

We move all terms containing f to the left, all other terms to the right

-2f=3

f=3/-2

f=-1+1/2

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